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| CHENMKO ENTERPRISE CO.,LTD SURFACE MOUNT Dual Digital Silicon Transistor VOLTAGE 50 Volts APPLICATION * Switching circuit, Inverter, Interface circuit, Driver circuit. CHUMH2PT CURRENT 30 mAmpere FEATURE * Small surface mounting type. (SC-88/SOT-363) * High current gain. * Suitable for high packing density. * * * * Low colloector-emitter saturation. High saturation current capability. Two CHDTC144E transistors in one package. Built in bias resistor(R1=47k, Typ. ) SC-88/SOT-363 (1) (6) 1.2~1.4 0.65 0.65 2.0~2.2 (4) 0.15~0.35 (3) 1.15~1.35 0.08~0.15 0.1 Min. 0.8~1.1 0~0.1 2.15~2.45 CIRCUIT 3 R1 R2 1 R2 4 R1 6 Dimensions in millimeters SC-88/SOT-363 LIMITING VALUES In accordance with the Absolute Maximum Rating System (IEC 60134). SYMBOL VCC VIN IO DC Output current IC(Max.) PTOT TSTG TJ RJ-A Note 1. Transistor mounted on an FR4 printed-circuit board. 2003-07 PARAMETER Supply voltage Input voltage CONDITIONS - MIN. MAX. 50 +40 30 V V UNIT -10 - - Tamb 25 OC, Note 1 - -55 - junction - ambient air - mA 100 200 +150 150 625 mW O Total power dissipation Storage temperature Junction temperature Thermal resistance C C C/W O O RATING CHARACTERISTIC ( CHUMH2PT ) CHARACTERISTICS Tamb = 25 C unless otherwise specied. SYMBOL VIoff) VI(on) VO(on) II IC(off) hFE R1 R2/R1 fT PARAMETER Input off voltage Input on voltage Output voltage Input current Output current DC current gain Input resistor Resistor ratio Transition frequency IE=-5mA, VCE=10.0V f=100MHz = CONDITIONS IO=100uA; VCC=5.0V IO=2mA; VO=0.3V IO=10mA; II=0.5mA VI=5V VI=0V; VCC=50V IO=5mA; VO=5.0V - - - - 68 32.9 0.8 - MIN. 0.5 - - - - - - 47 1.0 250 TYP. MAX. - 3.0 0.3 0.18 0.5 - 61.1 1.2 - K MHz V V mA uA UNIT Note 1.Pulse test: tp300uS; 0.02. RATING CHARACTERISTIC CURVES ( CHUMH2PT ) Typical Electrical Characteristics Fig.1 Input voltage vs. output current (ON characteristics) 100 50 VO=0.3V Fig.2 Output current vs. input voltage (OFF characteristics) 10m 5m OUTPUT CURRENT : Io (A) VCC=5V INPUT VOLTAGE : VI(on) (V) 20 10 5 2 1 500m 200m 100m 100 200 500 1m 2m 5m 10m 20m 50m 100m Ta =- 40OC 25OC = 100OC 2m 1m 500 200 100 50 20 10 5 2 1 0 Ta=100OC 25OC -40 OC 0.5 1.0 1.5 2.0 2.5 3.0 OUTPUT CURRENT : IO (A) INPUT VOLTAGE : VI(off) (V) Fig.3 DC current gain vs. output current 1k 500 DC CURRENT GAIN : GI Fig.4 Output voltage vs. output current 1 500m OUTPUT VOLTAGE : VO(on) (V) VO =5V Ta=100OC 25OC -40OC lO/lI=20 Ta=100OC 25OC -40 OC 200 100 50 20 10 5 2 200m 100m 50m 20m 10m 5m 2m 1 100 200 500 1m 2m 5m 10m 20m 50m100m 1m 100 200 500 1m 2m 5m 10m 20m 50m 100m OUTPUT CURRENT : IO (A) OUTPUT CURRENT : IO (A) |
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